Lets take stock horsepower numbers of a 2nd Gen 3000gt:

320hp * 760 watt/hp = 243,200 watts

Now thats a lot of power. Now take 25% of that...

243,200 * .25 = 60,800 watts.

That is an enourmous amount of power going somewhere....mostly into heat if you guys are correct about the 25% drivetrain loss. So 60KW of power is going into heat.

Now lets say that you drive at maximum horsepower for 1 hour.

We have...

60,800 joules/sec * 3600 seconds/hour = 218,880,000 joules

Thats 218.8 Megajoules that is dissappaited in the drivetrain. Where is all this energy going? I can't belive it would go into heat, or the differential would melt down. I just don't think theres that much drivetrain loss.

BTW, the rest of the horsepower goes into losses of tires on the road (very small percentage) and wind resistance which goes on the velocity squared, or it takes 4 times as much power to go twice as fast.

What are your thoughts on this? I know alot of you say that its not possible to move a 4000 pound car a quarter mile in 13.5 seconds with 320 hp, but torque curves have a lot to do with it. If you take the area under the torque curve for a vr4, you're going to find it has more area than a naturally asperated car with same maxium torque. Area under the torque curve should be a pretty good measure of 1/4 mile time.